maths answer tell me guys but only 3 or 4
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Nice questions ans is opson number 4
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since AS=BC
THEREFORE,. BC=AB=AC (being the radii)
hence in ∆ABC,
it is an equilateral triangle hence angle A=B=C=60°
now as it is quite visible that BS is a diameter, Therefore Angle BAS=180°
3.Angular measure of arcCBS
= angle CAB +BAS = 60°+180°=240°
4.FOR arc(SCB)= it's just the semicircle, hence the angle being 180°
and this is our Answers
THEREFORE,. BC=AB=AC (being the radii)
hence in ∆ABC,
it is an equilateral triangle hence angle A=B=C=60°
now as it is quite visible that BS is a diameter, Therefore Angle BAS=180°
3.Angular measure of arcCBS
= angle CAB +BAS = 60°+180°=240°
4.FOR arc(SCB)= it's just the semicircle, hence the angle being 180°
and this is our Answers
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