Math, asked by pvmrugesh, 4 days ago

maths
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Answered by RituS4
2

Answer:

2) (D) y - 81 = 7y

3) (B) 9/2

4) (A) 27

5) (B) x² - 5x - 14

6) (D) 3x² - 15x + 16

7) (B) Not real

8) (C) Real and equal

9) (D) Real and unequal

Explanation:

2) Rewriting the equation in standard format, the coefficient of y² is 0 in option (D)

3) Let the root be x, then

x+x = 2x = -b/a = -(-6)/2 = 3

⇒ x = 3/2

Also,

x² = c/a

(3/2)² = k/2

k = 3×3/2 = 9/2

4) Discriminant = b² - 4ac = (5√3)² - 4×2×6 = 75 - 48 = 27

5) x² - 5x - 14 = x² + 2x - 7x - 14 = x(x + 2) - 7(x + 2) = (x + 2)(x - 7)

Roots = -2, 7

6) α + β = -b/a = 5

-(-15)/3 = 5

Hence verified

7) Since the value of b² - 4ac is negative and it's not possible to root negative numbers, the roots of the quadratic equation is not real

8) b² - 4ac is 0 and since 0 does not have positives or negatives, both roots of the equation have equal value

9) b² - 4ac is a positive value, and since root of a positive number has 2 real and unequal values, the root of the equation also has 2 real and unequal values

Hope this helped :)

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