maths AP questions please fast
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6-(2k+1)=(3k+1)-6
10=5k
k=2✓
10=5k
k=2✓
Answered by
3
hello there!!!!!
ATQ,
first term , a1 = 2K + 1
2nd. , a2 = 6
3rd. , A3 = 3k + 1
If they forms an AP , then common difference ,d is same .
a2 - a1 = d.......(1). a3 - a2 = d.........(2)
from equal.(1) & (2) ,
a2 - a1 = a3 - a2
2 a2 = a3 + a1
2× 6 = 3k + 1 + 2k +1
12. = 5k + 2
10. = 5k
k = 10 / 5 = 2
•
• • K = 2
hope it helps ⭐⭐⭐⭐
bebrainly2 ⭐⭐⭐⭐
ATQ,
first term , a1 = 2K + 1
2nd. , a2 = 6
3rd. , A3 = 3k + 1
If they forms an AP , then common difference ,d is same .
a2 - a1 = d.......(1). a3 - a2 = d.........(2)
from equal.(1) & (2) ,
a2 - a1 = a3 - a2
2 a2 = a3 + a1
2× 6 = 3k + 1 + 2k +1
12. = 5k + 2
10. = 5k
k = 10 / 5 = 2
•
• • K = 2
hope it helps ⭐⭐⭐⭐
bebrainly2 ⭐⭐⭐⭐
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