Question

Maths Aryabhatt hai kya yha koii
50 pts


(a+b)(c-d)(a-b)(c+d)+2(ac+bd)

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Answer 1

$(a + b)(c - d)(a - b)(c + d) + 2(ac + bd) \\ = ( {a}^{2} - {b}^{2} )( {c}^{2} - {d}^{2} ) + 2ac + 2bd \\ = {a}^{2} ( {c}^{2} - {d}^{2} ) - {b}^{2}( {c}^{2} - {d}^{2} ) + 2ac + 2bd \\ = {a}^{2} {c}^{2} - {a}^{2} {d}^{2} - {b}^{2} {c}^{2} + {b }^{2} {d}^{2} + 2ac + 2bd$

$\textbf{\red{\large{Hope it helps}}}$

Answer 2

Answer:

Step by step solution :

Step 1 :

Equation at the end of step 1 :

(((a+b)•(c-d))+((a-b)•(c+d)))+2•(ac+bd)

Step 2 :

Equation at the end of step 2 :

(((a+b)•(c-d))+(a-b)•(c+d))+2•(ac+bd)

Step 3 :

Equation at the end of step 3 :

((a+b)•(c-d)+(a-b)•(c+d))+2•(ac+bd)

Step 4 :

Final result :

4ac