Question

Maths Assignment 2019-20
Class:X
0.1 Find the value of k for which the given equation has real and equal roots :
(1) 3(k + 1)^+ 2(k + 1) x + 1 = 0. (1) x2 + k(4x + K-1) + 2 =0. [Ans.
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Answer 1

(1)3(k+1)x^2+2(k+1)x+1=0

D=b^2-4ac

[2(k+1)]^2-4×(3k+3)(1)=0

4k^2+12+8k-12k-12=0

4k^2-4k=0

4k(k-1)=0

k=0&1