maths both ques please answer
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Let angle A &B is 2x and ,7x
=>2x+7x=180°
=>9x=180°
=>x=20°
A=40° B=140°
C&D in2x&3x
=>5X=180°
=>x=36°
C=72° D=108°
=>2x+7x=180°
=>9x=180°
=>x=20°
A=40° B=140°
C&D in2x&3x
=>5X=180°
=>x=36°
C=72° D=108°
Answered by
1
(I) angleA : angleB = 2 : 7
let the constant ratio be 'x'
sum of the consecutive angles of parallelogram = 180°
2x + 7x = 180
x = 20
angleA = 2x = 2(20) = 40°
AngleB = 7x = 7(20) = 140°
(ii)
angleC = 2/ 3 of angle D
= 2D/ 3
angleC + angleD = 180°
(2D/3) + D = 180°
5D = 540 => D = 108°
AngleD = 108°
angleC = 2D/ 3 = 2(108)/ 3 = 72°
let the constant ratio be 'x'
sum of the consecutive angles of parallelogram = 180°
2x + 7x = 180
x = 20
angleA = 2x = 2(20) = 40°
AngleB = 7x = 7(20) = 140°
(ii)
angleC = 2/ 3 of angle D
= 2D/ 3
angleC + angleD = 180°
(2D/3) + D = 180°
5D = 540 => D = 108°
AngleD = 108°
angleC = 2D/ 3 = 2(108)/ 3 = 72°
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