Question

maths calss 10 chapter 3 need answer it urgent for me. don't give me wrong answer .only 10 to upper class student solve this​

Answer 1

M not in 10th but the question was easy...

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Answer 2

Answer:

m=−2/x=−1

Step-by-step explanation:

Given equations are  

2x+3y=11−−−−(1)

2x−4y=−24−−−−(2)

Form (1)

2x+3y=11  

⇒2x=11−3y

⇒x= (11−3y)/2     −−−(3)

substituting  x in(2)

2x−4y=−24

⇒2(  11−3y )/2  −4y=−24

⇒11−3y−4y=−24

⇒11−7y=−24

⇒7y=35

⇒y=35/7

⇒y=5.

putting  y = 5 in (3)

x=  11−3(5) /2

⇒x=  11−15 /2

⇒x=−4/2

​ ∴x=−2.

Hence x = -2 and y = 5 is the solution of the  

equation.

Now, we have to find m

y=mx+3                                  ∴m=−1

​ 5=3(−2)+3

5−3=−2m⇒−2m=2

⇒m=−2/x=−1

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