Question

Maths cbse class 10 solution for the perimeter of a rectangular plot is 62 metre and its area is 228 square metre. find the dimensions of the plot

Answer 1

2(l+b)=62
lb=228
l+b=62/2=31
l=31-b
so (31-b)b=31b-b²=228=
b²-31b+228
=b²-19b-12b+228
=b(b-19)-12(b-19)
=(b-12)(b-19)
=b=12 or b=19
hence,l=19 or 12

Answer 2

☆ SoluTion =》

Answer:-

Dimensions are 19 and 12

Given =》

perimeter = 62m

Area = 228m²

To Find =》

Dimensions of the plot =?

Explanation =》

Perimeter = 2(l+b)

62=2(l+b)

62/2=l+b

31=l+b

l= 31-b

Area = 228

l×b= 288

(31-b)×b= 228

b²-31b -228=0

b²-(19+12)-228=0

b²-19b-12b-228=0

b(b-19)-12(b-19)=0

(b-19)(b-12)

b-19=0, b-12=0

b=19, b=12

If length = 19 then breadth = 31-19=12m

If length = 12 then breadth = 31-12= 91m.