Question

Maths ch1 pg1.35 q5 SM

Plz explain in detail step by step ​

Answer 1

ANSWER:

$\bf (a) 1$

STEP-BY-STEP VERIFICATION:

${( {x}^{\frac{1}{a - b} } )}^{ \frac{1}{a - c} } \times {( {x}^{\frac{1}{b - c} } )}^{ \frac{1}{b - a} } \times {( {x}^{\frac{1}{c - a} } )}^{ \frac{1}{c- b} }$

$= {x}^{ \frac{1}{(a - b)(a - c)} } \times {x}^{ \frac{1}{(b- c)(b- a)} } \times {x}^{ \frac{1}{(c - a)(c - b)} }$

$= {x}^{ \frac{1}{(a - b)(a - c)} +{ \frac{1}{(b - c)( b- a)} } +{ \frac{1}{(c- a)(c - b)} } }$

$= {x}^{ \frac{1}{(a - b)(a - c)} - { \frac{1}{(b - c)( a - b)} } +{ \frac{1}{(a - c)(b - c)} } }$

$= {x}^{ \frac{(b - c) - (a - c) +(a - b) }{(a - b)(a - c)(b - c)} }$

$= {x}^{ \frac{b - c - a + c +a - b }{(a - b)(a - c)(b - c)} }$

$= {x}^{ \frac{0 }{(a - b)(a - c)(b - c)} }$

$= {x}^{0}$

$= 1$

SO, THE ANSWER IS:

(A) 1

Answer 2

hope it helps I wrote in a rush