Question

maths class 10 cbse ncert ​

Answer 1

Answer:

A) 15√3m

Step-by-step explanation:

Let AB be the object of height 15m.

Let BC be the length of the shadow of the object such that ∠ACB=30°.

Now,

tan30= AB/BC

⇒1/√3= 15/BC

⇒BC= 15√3m

So, length of the shadow of the object is 15√3m.

I hope it will help you....