Maths class 10
Find the value of 'p' for which the quadratic polynomial has real linear factors:
px² + 2x + k = 0
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real linears factors are the first degree of equation
so value of x if 1
wo put the value of 1 in x
px²+2x+k=0
p(1)²+2(1)+k=0
p+2+k=0
p+k= -2 .........eq¹
k = -2+p ...........eq2
put the value of 2 eq in eq 1
p+(-2+p) = -2
p-2+p = -2
2p=0
p=0
now put the value of p in eq 2
k= -2+p
k= -2+0
k=-2
so the value of p=0 and k= -2
hope it will help you
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Answer:
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