Question

maths class 11 question ​

Answer 1

Answer:

$\huge\bold\red{ANSWER}$

Step-by-step explanation:

$\large{\underline{\rm{\red{SOLUTION :}}}}$

$\implies \sf centre\:of\:circle\:is\: (0,-4)\\ \\ \imples \sf i.e.\: O(0,-4)\\ \\ \implies \sf the\:point\:on\:the\:circle\:is\:P(\sqrt{13},2)\\ \\ \implies \sf the\:distance\:between\:the\:points\:gives\:radius\:of\:circle\\ \\ \sf Distance\:formulae=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\ \\ \implies \sf \sqrt{(\sqrt{13}-0)^2+(2+4)^2)}\\ \\ \implies \sf \sqrt{(13+36)}\\ \\ \implies \sf \sqrt{49}\\ \\ \implies \sf 7$