Question

maths class 7. congruence in triangles
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Answer 1

Step-by-step explanation:

angle A =angle C (given)

AB=CB(given)

BD=BD(common in ∆ABD&∆CBD)

∆ABD~= ∆CBD(bySSA)

Answer 2

Try to apply RHS congruence criterion!

Step-by-step explanation:

In ∆ABD & ∆CBD,

Angle A = Angle C (Each 90°)

BD = BD (Common)

AB = CD (Given)

So, ∆ABD is congruent to ∆CBD (By RHS congruence criterion)

Note:

There is no SSA congruence criterion in Triangle Congruence.

Therefore, Riya Bhalla's answer is absolutely wrong and incorrect.