Question

Maths Class 7 ICSE Anybody can help? It's urgent
BODMAS RULE

Answer 1

Given :

$\\ \red \bigstar \tt \: \frac{1}{3} \: of \frac{ \bigg(\frac{1}{3} + \frac{1}{3} \bigg)}{ \frac{1}{3} } - \bigg ( \frac{1}{3} \times \bigg \{ \frac{1}{3} - \frac{1}{3} \times \frac{1}{3} + \bigg( \frac{1}{3} + \frac{1}{3} \bigg) \bigg \} \bigg)$

To find :

➡ The remainder of this question =?

Solution :

$\\ \implies \sf \: \frac{1}{3} \: of \: \frac{ \bigg(\frac{1}{3} + \frac{1}{3} \bigg) }{ \frac{1}{3} } - \bigg( \frac{1}{3} \times \bigg \{ \frac{1}{3} - \frac{1}{3} \times \frac{1}{3} + \bigg(\dfrac{1}{3}+\dfrac{1}{3} \bigg) \bigg\} \bigg)$

$\\ \implies \sf \: \frac{1}{3} \: of \: \frac{ \bigg(\frac{1}{3} + \frac{1}{3} \bigg) }{ \frac{1}{3} } - \bigg( \frac{1}{3} \times \bigg \{ \frac{1}{3} - \frac{1}{3} \times \frac{1}{3} + \bigg( \frac{1}{3} + \frac{1}{3} \bigg) \bigg \} \bigg) \\ \\ \\ \implies \sf \: \frac{1}{3} \times \frac{ \frac{2}{ \cancel3} }{ \frac{1}{ \cancel3} } - \bigg( \frac{1}{3} \times \bigg \{ \frac{1}{3} - \frac{1}{9} + \bigg( \frac{2}{3} \bigg) \bigg \} \bigg) \\ \\ \\ \implies \sf \: \frac{1}{3} \times 2 - \bigg( \frac{1}{3} \times \bigg \{ \frac{1 \times 3}{3 \times 3} - \frac{1}{9} + \frac{2}{3} \bigg \} \bigg) \\ \\ \\ \implies \sf \: \frac{2}{3} - \bigg( \frac{1}{3} \times \bigg \{ \frac{2}{9} + \frac{2 \times 3}{3 \times 3} \bigg \} \bigg) \\ \\ \\ \implies \sf \: \frac{2}{3} - \bigg( \frac{1}{3} \times \bigg \{ \frac{8}{9} \bigg \} \bigg) \\ \\ \\ \implies \sf \: \frac{2}{3 } - \bigg( \frac{1}{3} \times \frac{8}{9} \bigg) \\ \\ \\ \implies \sf \: \: \frac{2}{3} - \bigg( \frac{8}{27} \bigg) \\ \\ \\ \implies \sf \: \bigg( \frac{2 \times 9}{3 \times 9} - \frac{8}{9} \bigg) \\ \\ \\ \implies \sf \: \frac{18 - 8}{27} \\ \\ \\ \implies \boxed{ \sf{ \frac{10}{27} }}$

➡ The answer will be 10/27

Answer 2

Answer:

10/27 is ur answer dear