Question

MATHS
CLASS = 8

22.Find the area of a rhombus whose one side measures 5 cm and one diagonal as 8 cm.

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Answer 1

Area of Rhombus is 24.

Step-by-step explanation:

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Answer 2

Answer:

Area of Rhombus is 24 $cm^2$

$\huge \mathbb \purple{\boxed{EXPLANATION}}$

Properties of Rhombus says-

Diagonals are ⊥ Bisector

• Therefore, the diagonal of 8 cm is divided into two segments 4 cm long. Using the Pythagorean Theorem and any of the right triangles to solve for x.

$5^2 = 4^2 + x^2$

$x^2 = 25 - 16$

$x^2 = 9$

x = 3

As per the formula for rhombus, Area, $A = \frac {1}{2} d_1d_2$

Where are diagonals

$d_1 = 8 cm$

$d_2 = 6 cm$

$A = \frac {1}{2} \times 8 \times 6$

$\tt \red{\boxed{A = 24\ cm^2}}$

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