maths class 8
show the processing as well
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Step-by-step explanation:
Given:
y=5\sf \: y=5y=5
z=8\sf \: z=8z=8
ToFind:\sf\red{To \:Find :}ToFind:
valueofx\sf \: value \: of \:xvalueofx
Solution:\sf\red{Solution:}Solution:
z=2xyx+y\sf \: z = \dfrac{2xy}{x + y}z=
x+y
2xy
puttingthevalueofz,weget\sf \: putting \: the \: value \: of \: z, \: we\: getputtingthevalueofz,weget
⟹8=2×x×5x+5\sf \:⟹ 8 = \dfrac{2×x×5}{x + 5}⟹8=
x+5
2×x×5
⟹8=10xx+5\sf \:⟹ 8= \dfrac{10x}{x +5}⟹8=
x+5
10x
⟹8(x+5)=10x\sf \:⟹{8(x + 5)} = 10x⟹8(x+5)=10x
⟹8x+40=10x\sf \:⟹8x + 40 = 10x \:⟹8x+40=10x
⟹8x−10x=−40\sf \: ⟹8x-10x= -40 \:⟹8x−10x=−40
⟹−2x=−40\sf \:⟹-2x= -40⟹−2x=−40
⟹x=−40−2\sf \:⟹x=\dfrac{-40}{-2}⟹x=
−2
−40
⟹x=20
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