Question

Maths class 9th chapter 2 question ​

Answer 1

Step-by-step explanation:

$x + 2 = 0 \\ x = - 2$

$p(x) = {x}^{4} + 3 {x}^{3} + {x}^{2} + 1$

p(-2)=(-2)^4+3(-2)^3+(-2)^2+1=R

=16-24+4+1=R

21-24=R

-3=R

$q(x) = {x}^{2} + rx - 154$

x2+Rx-154=0

x2-3x=154

x2-x=154/3

x2=154/4+x

x=√154/4+x