Math, asked by manidarling39923, 1 year ago

maths dout as shown in above photo you want to prove that

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Answered by indiravalar3
1

Answer:


Step-by-step explanation:


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Answered by chandresh126
0

Answer:

=> X = (-1) \left[\begin{array}{ccc}16&14\\21&32\end{array}\right]

Step-by-step explanation:

Hey Mate,


A = \left[\begin{array}{ccc}9&1\\4&3\end{array}\right]

B = \left[\begin{array}{ccc}1&5\\6&11\end{array}\right]

3 A = 3  \left[\begin{array}{ccc}9&1\\4&3\end{array}\right]

=> \left[\begin{array}{ccc}27&3\\12&9\end{array}\right]

5 B = 5  \left[\begin{array}{ccc}1&5\\6&11\end{array}\right]

=>   \left[\begin{array}{ccc}5&25\\30&55\end{array}\right]


We have to find : => 3A + 5B +2X = 0

3A + 5B + 2X = \left[\begin{array}{ccc}27&3\\12&9\end{array}\right] +  \left[\begin{array}{ccc}5&25\\30&55\end{array}\right] + 2X = 0


=>  \left[\begin{array}{ccc}32&28\\42&64\end{array}\right] + 2X = 0


=> 2X = - \left[\begin{array}{ccc}32&28\\42&64\end{array}\right]


=> X = (-1) \left[\begin{array}{ccc}16&14\\21&32\end{array}\right]


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