Question

maths dout as shown in above photo you want to prove that

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Answer:

=> X = (-1) $\left[\begin{array}{ccc}16&14\\21&32\end{array}\right]$

Step-by-step explanation:

Hey Mate,

A = $\left[\begin{array}{ccc}9&1\\4&3\end{array}\right]$

B = $\left[\begin{array}{ccc}1&5\\6&11\end{array}\right]$

3 A = 3  $\left[\begin{array}{ccc}9&1\\4&3\end{array}\right]$

=> $\left[\begin{array}{ccc}27&3\\12&9\end{array}\right]$

5 B = 5  $\left[\begin{array}{ccc}1&5\\6&11\end{array}\right]$

=>   $\left[\begin{array}{ccc}5&25\\30&55\end{array}\right]$

We have to find : => 3A + 5B +2X = 0

3A + 5B + 2X = $\left[\begin{array}{ccc}27&3\\12&9\end{array}\right]$ +  $\left[\begin{array}{ccc}5&25\\30&55\end{array}\right]$ + 2X = 0

=>  $\left[\begin{array}{ccc}32&28\\42&64\end{array}\right]$ + 2X = 0

=> 2X = - $\left[\begin{array}{ccc}32&28\\42&64\end{array}\right]$

=> X = (-1) $\left[\begin{array}{ccc}16&14\\21&32\end{array}\right]$