Question

maths exam...question..​

Answer 1

$\color{red}\huge{\underline{\underline{GIVEN\dag}}}$

• $\angle ABC = 72 \degree$
• $\angle ACB = 45 \degree$

$\color{red}\huge{\underline{\underline{SOLUTION\dag}}}$

Consider $\triangle ABC$;

By ANGLE SUM PROPERTY;

$\angle BAC+\angle ABC+\angle ACB=180°$

$\angle BAC+72°+45°=180°$

$\angle BAC+117°=180°$

$\angle BAC=63°.......(1)$

We know that;

Angles in the same segment and standing on the same chord are always equal.

$\implies \angle BDC=\angle BAC$

From (1);

$\orange{\boxed{\therefore \angle BDC=53°}}$

HOPE THAT HELPS!!