maths geometry plzzzz very urgent
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In triangle ABC,
since AB=AC, therefore angle ABC=angle ACB(angles opposite to equal sides are equal)
In triangle OBC,
since OB=OC, therefore angle OBC= angle OCB
Subtract the second result from the first,
angle ABC-angleOBC=angle ACB-angleOCB
angle ABO=angleACO
since AB=AC, therefore angle ABC=angle ACB(angles opposite to equal sides are equal)
In triangle OBC,
since OB=OC, therefore angle OBC= angle OCB
Subtract the second result from the first,
angle ABC-angleOBC=angle ACB-angleOCB
angle ABO=angleACO
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