maths In an AP if a=5,d=3 find T 10
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T 10. = a + 9 d
= 5 +9 .3
= 5 + 27
= 32
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Answer:
t₁₀ = 32
Step-by-step explanation:
In an AP,
tₙ = a + (n-1)d
where,
tₙ = nth term
a = first term
d = common difference
given,
a=5 ; d=3 ; t₁₀ = ?
tₙ = a + (n-1)d
t₁₀ = 5 + (10-1)3
t₁₀ = 5 + (9 x 3)
t₁₀ = 5 + 27
t₁₀ = 32
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