Question

Maths is getting tougher..... xD

Here's a question for u guys to show and prove ur self a maths aryabhata..... xD. Just a good question. Hope to receive good answers.

$\sqrt{ \frac{x}{ x - 3} } + \sqrt{ \frac{x - 3}{x} } = \frac{5}{2}$
Want the solution in a great detail without even a single step skipping.

Answer 1

Hey user !! your solution is here in the attachment :-

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( Note : we have mainly used substitution method fo the

given probem ) :-

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By solving the equations we get the value of x = -1 & 4

lets check this value by substituting the values in the given equations

= $\sqrt\frac{x}{x-3} + \sqrt\frac{x-3}{x} = \frac{5}{2}$

= $\sqrt\frac{4}{4-3} + \sqrt\frac{4-3}{4} = \frac{5}{2}$

=$\sqrt\frac{4}{1}  + \sqrt\frac{1}{4} = \frac{5}{2}$

=$2 + \frac{1}{2} = \frac{4+1}{2} = \frac{5}{2}$

Now insert the value of x = -1

= $\sqrt\frac{-1}{-1-3} + \sqrt\frac{-1-3}{-1} = \frac{5}{3}$

= $\sqrt\frac{1}{4} + \sqrt\frac{4}{1} = \frac{5}{3}$

And hence it is proved

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