Question

maths legend help me to solve this​

Answer 1

${(4 - \frac{1}{3x}) }^{3} = \frac{ {1728x}^{3} - {432x}^{2} + 36x - 1 }{ {27x}^{3} }$

The explanation has been attached in the given attachment.

Answer 2

Answer:

$(4 - \frac{1}{3x} ) {}^{3}$

using identity

(a-b) = a³ - b³ - 3ab(a-b)

$= (4) {}^{3} - ( \frac{1}{3x} ) {}^{3} - 3(4)( \frac{1}{3x} )(4 - \frac{1}{3x} )$

$= 64 - \frac{1}{27x {}^{3} } - \frac{4}{3x} (4 - \frac{1}{3x} )$

$= 64 - \frac{1}{27x {}^{3} } - \frac{16}{3x} - \frac{4}{9x {}^{2} }$