Maths Legends can Solve...!!
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Topic :-
3D - Coordinate Geometry
Given :-
The points (8, -5, 6), (11, 1, 8), (9, 4, 2) and (6, -2, 0) are vertices of a cyclic quadrilateral.
To Find :-
Area of the given quadrilateral.
Concept Used :-
Distance between two points
Solution :-
Let points be A (8, -5, 6), B (11, 1, 8), C (9, 4, 2) and D (6, -2, 0).
Calculating Distance between points,
We observe that all sides of given Quadrilateral are equal and diagonals are also equal to each other, which means given quadrilateral is a Square of side 7 units.
Area of Square = ( Side )²
Area of Square = ( 7 units)²
Area of Square = 49 sq. units
Answer :-
So, the area of given Quadrilateral which is a square is 49 sq. units.
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