Question

maths physics please solve​

Answer 1

Answer:

please give me brainlist answer then i will tell

Answer 2

$\huge\mathcal{\fcolorbox{cyan}{black}{\pink{ANSWER}}}$

Some formula that you have to know :

$\green \odot \: \: \: \frac{d \: (uv)}{dx} = u \times \frac{d \: v}{dx} + v \times \frac{d \: u}{dx} \\ \\ \green \odot \: \: \: \frac{d \: sin \: x}{dx} = cos \: x \\ \\ \green \odot \: \: \: \frac{d \: {x}^{n} }{dx} = n {x}^{n - 1}$

Now,

$\: \: \: \: \: \: \: \: y = {x}^{2} \: . \: sin \: x \\ \implies \: \frac{dy}{dx} = \frac{d( {x}^{2} \: sin \: x )}{dx} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = {x}^{2} \times \frac{d \: sin \: x}{dx} + sin \: x \: \times \frac{d \: {x}^{2} }{dx} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = {x}^{2} \times cos \: x + \: sin \: x \: \times \: \: 2x \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = {x}^{2} cos \: x + 2x. \: sin \: x$

So option ( A ) is the correct answer.