Question

maths pls ans my question​

Answer 1

Step-by-step explanation:

i hope that answer help you

Answer 2

1.

$3 \sqrt[3]{40} - 4 \sqrt[3]{320} \\ = 3 \times 2 \sqrt[3]{5} - 4 \times 4 \sqrt[3]{5} \\ = 6 \sqrt[3]{5} - 16 \sqrt[3]{5} \\ = - 10 \sqrt[3]{5}$

2.

$\frac{1}{x} = \frac{1}{ \sqrt{2} + 1} \\ = \frac{1}{ \sqrt{2} + 1 } \times \frac{ \sqrt{2} - 1 }{ \sqrt{2} - 1} \\ = \frac{ \sqrt{2} - 1 }{2 - 1} \\ = \frac{ \sqrt{2} - 1}{1} = \sqrt{2} - 1$

$x + \frac{1}{x} = \sqrt{2} + 1 + \sqrt{2} - 1 \\ x + \frac{1}{x} = 2 \sqrt{2}$

3.

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4.

Refer to Image.