maths plzzzzz help
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Given ABCD is a quadrilateral [Note: Not a Trapezium]
angle ADC = y
angle ABC = x
angle DEA = b
angle BCF = a
since we know that ,
Sum of angles on a Straight line is 180°
and Sum of angles in a Quadrilateral is 360°
then,
angle DAB = (180 - b)° and angle BCD = (180 - a)°
now in Quad. ABCD
angle ADC + angle ABC + angle DAB + angle BCD = 360°
putting the values ,
y + x + (180 - b) + (180 - a) = 360°
x + y - a - b + 360 = 360
x + y - a - b = 0
x + y = a + b
therefore , correct option is (A).
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I hope you understand.
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