❍ Maths Problem !!
◉ A sum of money invested at 9% per annum simple interest amounts to ₹37760 in 2 years. What will it amount to in 3 years at 10% per annum ?
❍ Chem. Problem !!
◉ Give :-
➯ The table of Monovalent Ion or radical with their formulae .
❍ History Problem !!
◉ Revenue system of Akbar .
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Answers
✰ Math's Solution !!
☯ Given :
- A sum of money invested at 9% per annum simple interest amounts to ₹ 37760 in 2 years.
☯ Exigency To Find : ㅤㅤ
- What will it amount to in 3 years at 10% per annum ?
☯ Formulae Used :
ㅤ ㅤ◉ S.I. ➠ ᴾ*ᴿ*ᵀ⁄₁₀₀
ㅤ ㅤ◉ Amount ➠ (Principal + Interest)
☯ Here :ㅤ ◉ P ➪ Principal
ㅤ ㅤ ㅤ ㅤ ◉ R ➪ Rate
ㅤ ㅤ ㅤ ㅤ ◉ T ➪ Time
ㅤ ㅤ ㅤ ㅤ ◉ S.I. ➪ Simple Interest
ㅤ ㅤ ㅤ ㅤ ◉ p.a. ➪ Per Annum
❍ Required Solution :
☯ Let, the sum be ₹100 . Then,
- P ➠ ₹100
- R ➠ 9% p.a.
- T ➠ 2 years.
.°. S.I. ➠ ᴾ*ᴿ*ᵀ⁄₁₀₀
☯ By substituting the values, we get :
➠ ¹⁰⁰*⁹*²⁄₁₀₀
➥ 18.
.°. Amount ➠ (Principal + Interest)
☯ By substituting the values, we get :
➠ (100 + 18)
➥ 118.
➠ If amount is ₹ 118, then sum ➪ ₹ 100.
➠ If amount is ₹ 1, then sum ➪ ₹ (¹⁰⁰⁄₁₁₈).
➠ If amount is ₹ 37760, then sum
ㅤ ➪ ₹ (¹⁰⁰⁄₁₁₈ × 37760).
ㅤ ➪ ₹ 322000.
☯ Now,
- P ➠ ₹32000
- R ➠ 10% p.a.
- T ➠ 3 years
.°. S.I. ➠ ᴾ*ᴿ*ᵀ⁄₁₀₀
☯ By substituting the values, we get :
➠ ³²⁰⁰*¹⁰*³⁄₁₀₀
➥ ₹ 9600
.°. Amount ➠ (Principal + Interest)
☯ By substituting the values, we get :
➠ (3200 + 9600)
➥ ₹ 41600.
.°. Hence, the required amount is ₹ 41600.
✰ Chemistry Solution !!
☯ Here's the table given below :: –
☯ Note ::–
- Kindly, see the table from site.
☯ Your Question's link :
- https://brainly.in/question/38704581?utm_source=android&utm_medium=share&utm_campaign=question
✰ History Solution !!
☯ Revenue System of Akbar ::–
- Refer to the attachment .
☯ Extra Info. about Akbar :
- Akbar issued a gold coin called mohur.
Answer:
✰ Math's Solution !!
☯ Given :
A sum of money invested at 9% per annum simple interest amounts to ₹ 37760 in 2 years.
☯ Exigency To Find : ㅤㅤ
What will it amount to in 3 years at 10% per annum ?
☯ Formulae Used :
ㅤ ㅤ◉ S.I. ➠ ᴾ*ᴿ*ᵀ⁄₁₀₀
ㅤ ㅤ◉ Amount ➠ (Principal + Interest)
☯ Here :ㅤ ◉ P ➪ Principal
ㅤ ㅤ ㅤ ㅤ ◉ R ➪ Rate
ㅤ ㅤ ㅤ ㅤ ◉ T ➪ Time
ㅤ ㅤ ㅤ ㅤ ◉ S.I. ➪ Simple Interest
ㅤ ㅤ ㅤ ㅤ ◉ p.a. ➪ Per Annum
❍ Required Solution :
☯ Let, the sum be ₹100 . Then,
P ➠ ₹100
R ➠ 9% p.a.
T ➠ 2 years.
.°. S.I. ➠ ᴾ*ᴿ*ᵀ⁄₁₀₀
☯ By substituting the values, we get :
➠ ¹⁰⁰*⁹*²⁄₁₀₀
➥ 18.
.°. Amount ➠ (Principal + Interest)
☯ By substituting the values, we get :
➠ (100 + 18)
➥ 118.
➠ If amount is ₹ 118, then sum ➪ ₹ 100.
➠ If amount is ₹ 1, then sum ➪ ₹ (¹⁰⁰⁄₁₁₈).
➠ If amount is ₹ 37760, then sum
ㅤ ➪ ₹ (¹⁰⁰⁄₁₁₈ × 37760).
ㅤ ➪ ₹ 322000.
☯ Now,
P ➠ ₹32000
R ➠ 10% p.a.
T ➠ 3 years
.°. S.I. ➠ ᴾ*ᴿ*ᵀ⁄₁₀₀
☯ By substituting the values, we get :
➠ ³²⁰⁰*¹⁰*³⁄₁₀₀
➥ ₹ 9600
.°. Amount ➠ (Principal + Interest)
☯ By substituting the values, we get :
➠ (3200 + 9600)
➥ ₹ 41600.
.°. Hence, the required amount is ₹ 41600.
✰ Chemistry Solution !!
☯ Here's the table given below :: –
\begin{gathered} \boxed{ \begin{tabular}{ c|c } \bf{Ion \: or \: radical }& \bf{Formulae} \\ \cline{1 - 2} \\1.\:Chloride &CI {}^{ - } \\\cline{1 - 2} 2.\: Bromide& Br{}^{ - }\\\cline{1 - 2}3.\:Iodide& I{}^{ - } \\\cline{1 - 2}4.\:Hydride &H{}^{ - } \\\cline{1 - 2}5.\:Nitrite& NO_2{}^{ - } \\\cline{1 - 2}6.\: Nitrate &No_3{}^{ - } \\\cline{1 - 2}7.\:Bicarbonate& HCO_3{}^{ - } \\\cline{1 - 2}8.\:Bisulphite& HSO_3{}^{ - } \\\cline{1 - 2}9.\:Bisulphide& HS{}^{ - } \\\cline{1 - 2}10.\:Bisulphate& HSO_4{}^{ - } \\\cline{1 - 2}11.\:Hydroxide& OH{}^{ - } \\\cline{1 - 2}12.\:Acetate & CH_{3}\rm{COO}{}^{ - } \end{tabular}} \end{gathered}
☯ Note ::–
Kindly, see the table from site.
☯ Your Question's link :
https://brainly.in/question/38704581?utm_source=android&utm_medium=share&utm_campaign=question
✰ History Solution !!
☯ Revenue System of Akbar ::–
Refer to the attachment .
☯ Extra Info. about Akbar :
Akbar issued a gold coin called mohur.
