Math, asked by king1151, 1 year ago

Maths problem.
ans fastly plllls..​

Attachments:

Answers

Answered by abhi569
1

Answer:

Value of a is 3 and value of b is 1.

Step-by-step explanation:

It is given that ( x + 2 ) is the factor of the given polynomial x^2 + ax + 2b, also a + b = 4 ,

By Factor Theorem : -

[ x - ( - 2  ) ] , value of f( - 2 ) should be 0,

= > f( x ) = x^2 + ax + 2b

= > f( - 2 ) = ( - 2 )^2 + a( - 2 ) + 2b = 0

= > 0 = 4 - 2a + 2b

= > 2a - 2b = 4

= > 2( a - b ) = 4

= > a - b = 2

= > a = 2 + b                  ...( i )

In the question, given, a + b = 4,

Now substituting the value of a from ( i )

= > ( 2 + b ) + b = 4

= > 2 + 2b = 4

= > 2b = 4 - 2

= > 2b = 2

= > b = 1

Substituting the value of b in ( i )

= > a = 2 + b

= > a = 2 + 1

= > a = 3


king1151: thanks mate.
king1151: mate ans my 2 questions also
abhi569: welcome
king1151: bhai copy me likh ke pic bhej skte ho
abhi569: Not possible
king1151: ok
Similar questions