Question

maths problem. correct answer shall be rewarded brainliest​

Answer 1

Step-by-step explanation:

Given,

Angle ABE = 100°

Angle ACD = 120°

We know that,

Angle ABE and Angle ABC are supplementary angles.

= Angle ABE + Angle ABC = 180°

= 100° + Angle ABC = 180°

= Angle ABC = 180°-100° = 80°

We know that,

Angle ACD and Angle ACB are supplementary angles.

= Angle ACD + Angle ACB = 180°

= 120° + Angle ACB = 180°

= Angle ACB = 180°-120° = 60°

Now,

We know that,

Angle ABC = 80° and Angle ACB = 60°

We also know that,

Angle ABC,Angle ACB and Angle BAC are the 3 angles in the given triangle.

That means,

Angle ABC + Angle ACB + Angle BAC = 180°

= 80° + 60° + Angle BAC = 180°

= Angle BAC = 180°- (80° + 60°)

= Angle BAC = 180° - 140° = 40°

All the angles of the given triangle are :

Angle ABE = 100°

Angle ACD = 120°

Angle ABC = 80°

Angle ACB = 60°

Angle BAC = 40°

Please mark me as the Brainliest and follow me....