Question

maths problem logarithms 2 power 2+log 3 base 2
${2}^{2 + log_{2}(3) }$
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Answer 1

Answer:

We know that

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i ) a^m+n = a^m × a^n ------( 1 )

ii) a^log (base a) ( x ) = x ----- ( 2 )

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According to the problem given,

2^2 + log ( base 2 ) ( 3 )

= 2^2 × 2^ log ( base 2 )(3 ) [ from (1)]

= 4 × 3 [ from ( 2 )]

= 12

I hope this helps you.

Step-by-step explanation: