Question

maths problem pls help....​

Answer 1

Answer:

x=28

y= 114

z= 20

Step-by-step explanation:

we know,

86+x+3z-6+y+2x+10 = 360

Also,

<AOD = <COB and <AOC=< BOD (Vertically opposite angles)

=> 86+x+2x+10+86+x+2x+10= 360

192+6x= 360

6x = 168

=> x = 28

y = 86+x

=86+28

= 114

Now

< DOB =2x+10

= 2(28)+10

= 66

also <AOC = 66

=> 3z-6 = 66

3z= 60

z = 20

Answer 2

Answer:

x=28, y=114, z=24

Step-by-step explanation:

in the given fig.,

CD is a straight line. so,

86+x+3z-6=180

x+3z=100 -----1

AB ia also a straight line,

so .,

x+86+2x+10=180

::x=28

substitute x=28 in equation 1,

we get z=24

in CD straight line,

2x+10+y=180

we already have x=28,

so, ::y=114