Question

Maths - Quadratic Equations
Solve​

Answer 1

Answer:

Step-by-step explanation:

17a^2-2a+10=10a^2+2a+7

Transposin’ RHS terms to LHS

17a^2-10a^2 -2a-2a+10-7 = 0

7a^2 -4a+3 = 0

Using factorisation,

7a^2-7a+3a+3=0

=> 7a(a-1)+3(a-1) =0

=> (7a+3)(a-1) = 0

=> 7a+3=0 or a-1= 0

=> a = -3/7 or a = 1

Answer 2

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17a^2-2a+10=10a^2+2a+7

Transposin’ RHS terms to LHS

17a^2-10a^2 -2a-2a+10-7 = 0

7a^2 -4a+3 = 0

Using factorisation,

7a^2-7a+3a+3=0

=> 7a(a-1)+3(a-1) =0

=> (7a+3)(a-1) = 0

=> 7a+3=0 or a-1= 0

=> a = -3/7 or a = 1