Question

maths question answer fast

Answer 1

Let the number be x.

Given that sum of a number and its reciprocal = 17/4.

x + 1/x = 17/4

(x^2 + 1)/x = 17/4

4x^2 + 4 = 17x

4x^2 - 17x + 4 = 0

4x^2 - 16x - x + 4 = 0

4x(x - 4) - 1(x - 4) = 0

(4x - 1)(x - 4) = 0

x = 1/4 (or) x = 4.


Verification:

x + 1/x = 1/4 + 1/(1/4)

            = 1/4 + 4

            = 17/4.


x + 1/x = 4 + 1/4

           = 17/4.


Hope this helps!

Answer 2

Hey there!

Let e original number be x

n' it's Reciprocal = 1/x

Then, According to Question

x + 1/x = 17/4

x² + 1 = 17/4x [multiplying the whole Eqn. by x]

x² - 17/4x + 1 = 0

4x² - 17x + 4 = 0 [multiplying whole Eqn. by 4]

(4x-1)(x-4) = 0

Applying Zero rule,
4x = 1
x = 1/4 and x = 4

Hence the two numbers = 4 n' 1/4

HOPE IT HELPED ^_^