maths question. attached pls answer all 3 question I mark you as brainlist
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Q7) LET THE THREE INTEGER BE X,X+1,X+2
= X+X+1+X+2 = 5+X
= 3X+3=5+X
= 3X-X = 5-3
= 2X = 2
X = 1
Q8) PERIMETER OF TRIANGLE = SUM OF ALL SIDES
= 30 = 9+9+X
= 30 = 18+X
= 30-18 = X
= 12 = X
Q9) LET ONE ANGLE BE X
SECOND ANGLE X + 10
THIRD ANGLE= X+20
SUM OF ANGLES IS 180 DEGREE
X + X +10+X+20=180
3X+30=180
3X= 150
X = 150/3
X = 50 DEGREE
SECOND ANGLE = 60 DEGREE
THIRD ANGLE = 70 DEGREE
PLZZ MARK BRAINLIEST
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