Question

maths question cbse class x​

Answer 1

Answer:

Proved

Step-by-step explanation:

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Answer 2

Proving:

Step-by-step explanation:

$\ Given \ value:\\\\(1 - sin \theta \ + cos \theta)^2 = \ 2 (1+ cos \theta) \ (1 - sin \theta)\\\\\ Solution:\\\\\ formula: \\\\\ (a-b+c)^2 = a^2+ (-b)^2+c^2+2(a(-b)+(-b)c+ca)\\\\\ L.H.S: \\\\\rightarrow (1 - sin \theta \ + cos \theta)^2\\\\\rightarrow ((1)^2 + (- sin \theta)^2 \ + (cos \theta)^2+2(1.(- sin \theta) + (- sin \theta).(cos \theta) + (cos \theta).(1))$

$\rightarrow (1 + sin^2 \theta \ + cos^2 \theta+2(- sin \theta - sin \theta \ cos \theta + cos \theta)\\\\\therefore \ sin^2 \theta \ + cos^2 \theta = 1\\\\\rightarrow (1 + 1-2sin \theta - 2sin \theta \ cos \theta + 2cos \theta)\\\\\rightarrow (2-2sin \theta - 2sin \theta \ cos \theta + 2cos \theta)\\\\\rightarrow (2+ 2cos \theta -2sin \theta - 2sin \theta \ cos \theta )\\\\\rightarrow (2(1+cos \theta) -2sin \theta (1+\ cos \theta )\\\\\rightarrow ((1+cos \theta) (2-2sin \theta)$

$\rightarrow (1+cos \theta). 2(1-sin \theta) \\\\\rightarrow \ 2(1+cos \theta)(1-sin \theta)$

L.H.S =R.H.S

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• Proving: https://brainly.in/question/3503668