maths question. chap volume
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Given,
Edge(side)=12cm
Volume =side^3
=》 12×12×12
Melted into 3 cubes of volume
cude with side 6cm
=6×6×6
cube with side8cm
=8x8x8
let the side be x
then
(8x8x8)+(6×6×6)+(x×x×x)=12×12×12
=》x^3=(12×12×12)-728
=》x^3=1728-728
=》x^3=1000
=》x=10
________
OR
________
⬇️⬇️⬇️⬇️
volume of cube is a^3
so, volume with side 12 cm is 12^3 = 1728
volume of cube with sides 6 cm is 6^3 =216
similarly for 8 cm is = 8^3 = 512
volume of third cube = 1728 - (216 +512) =1000
now ,a^3 = 1000
therefore a = 10 cm answer
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Edge(side)=12cm
Volume =side^3
=》 12×12×12
Melted into 3 cubes of volume
cude with side 6cm
=6×6×6
cube with side8cm
=8x8x8
let the side be x
then
(8x8x8)+(6×6×6)+(x×x×x)=12×12×12
=》x^3=(12×12×12)-728
=》x^3=1728-728
=》x^3=1000
=》x=10
________
OR
________
⬇️⬇️⬇️⬇️
volume of cube is a^3
so, volume with side 12 cm is 12^3 = 1728
volume of cube with sides 6 cm is 6^3 =216
similarly for 8 cm is = 8^3 = 512
volume of third cube = 1728 - (216 +512) =1000
now ,a^3 = 1000
therefore a = 10 cm answer
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ᏆͲ
ᎻᎬᏞᏢՏ
ᎽϴႮ
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arjun6068:
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Answered by
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Here is your answer:
edge of metal cube = 12
Volume of metal cube = a³
= 12³ = 12*12*12
Big metal cube is melted and formed into three smaller cubes.
Edge of 1st cube = 6 cm
Vol. of cube1 = a² = 6³ = 6*6*6
Edge of 2nd cube = 8 cm
Vol. of cube2 = a³ = 8³ = 8*8*8
Let edge of 3rd cube = x
So, Vol. of cube3 = x³
Now,vol. always remain same
Therefore,
Volume of big cube = volume of 3 small cube
12*12*12 = (8*8*8)+(6*6*6)+x³
1728 = 728 + x³
x³ = 1728-728
x³ = 1000
x³ = 10³
x = 10 cm
So, the edge of third cube
= 10 cm
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