Maths Question Class Xth
The number of zeroes that polynomial f(x)= (x-2)²+ 4 can have is:
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Answer:
f(x) = (x - 2)² + 4
f(x) = x² - 4x + 4 + 4
f(x) = x² - 4x + 8 X
If we find discriminant = b² - 4ac we get b² - 4ac
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Hence, the given quadratic polynomial has no real roots.
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