Math, asked by jaki2682, 9 months ago

Maths question

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Answers

Answered by tardymanchester
10

ANSWER :

The center is (1,-3) and the radius is r=5 units.

EXPLANATION :

The given equation is:

 {x}^{2}  +  {y}^{2}  - 2x + 6y - 15 = 0

Let rearrange to get:

{x}^{2}  - 2x +  {y}^{2} +  6y=15

We complete the square to get;

{x}^{2}  - 2x + ( { - 1)}^{2}  +  {y}^{2} +  6y   +  {3}^{2} =  15+ ( { - 1)}^{2} +  {3}^{2}

 ( {x - 1)}^{2}  +(  {y + 3)}^{2} =  15 + 1+  9

 ( {x - 1)}^{2}  +(  {y + 3)}^{2} =25

( {x - 1)}^{2}  +(  {y + 3)}^{2} = {5}^{2}

Comparing to

( {x - h)}^{2}  +(  {y  - h)}^{2} = {r}^{2}

The center is (1,-3) and the radius is r=5 units.


Anonymous: Help
Answered by Anonymous
2

Answer:

Step-by-step explanation:

ANSWER :

The center is (1,-3) and the radius is r=5 units.

EXPLANATION :

The given equation is:

Let rearrange to get:

We complete the square to get;

Comparing to

The center is (1,-3) and the radius is r=5 units.

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