Math, asked by Anonymous, 11 months ago

maths question for genius ..spams will be reported keep in mind...,...​

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Answered by adityayadav06050
0

Step-by-step explanation:

If roots are equal then D = 0

D of given eq. will equal to 0

D = b ^2 -4ac

d = (ab -ac)^2 -4 (ac -bc )(bc-ac) = 0

d = (ab)^2 +(ac)^2 - 2a^2bc -4 (abc^2 - a^2c^2-(bc)^2 + abc^2) =0

= (ab)^2 +(ac)^2 - 2a^2bc -4abc^2 +4(ac)^2

+4(bc)^2 -4abc^2 =0

= (ab)^2 +5 (ac)^2 - 2a^2bc -4abc^2

- 2a^2bc -4abc^2 +4(bc)^2 -4abc^2 =0

futhere might be some common values will come I'm not doing because it is so conjugated

Answered by supriths4804
0

Answer:

2bc= ab+ac

Step-by-step explanation:

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