maths question for genius ..spams will be reported keep in mind...,...
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Step-by-step explanation:
If roots are equal then D = 0
D of given eq. will equal to 0
D = b ^2 -4ac
d = (ab -ac)^2 -4 (ac -bc )(bc-ac) = 0
d = (ab)^2 +(ac)^2 - 2a^2bc -4 (abc^2 - a^2c^2-(bc)^2 + abc^2) =0
= (ab)^2 +(ac)^2 - 2a^2bc -4abc^2 +4(ac)^2
+4(bc)^2 -4abc^2 =0
= (ab)^2 +5 (ac)^2 - 2a^2bc -4abc^2
- 2a^2bc -4abc^2 +4(bc)^2 -4abc^2 =0
futhere might be some common values will come I'm not doing because it is so conjugated
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Answer:
2bc= ab+ac
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