maths question for toppers
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diameter=84 cm
radius= 42cm
length=1m =100cm
CurvedSurfaceArea= 2pierh
2×22/7×42×100
22×12
26400 cm^2
for 750 revolutions= 26400×750
=19800000cm^2
=1980m^2
radius= 42cm
length=1m =100cm
CurvedSurfaceArea= 2pierh
2×22/7×42×100
22×12
26400 cm^2
for 750 revolutions= 26400×750
=19800000cm^2
=1980m^2
Answered by
0
Hey !!
Given :- diameter of roller 84
r =42/2 cm
lenght /height of """"""""""" 1m =100cm
So, Curved surface area of road roller 2πrh because road roller is always in the form of cylindrical shape
so, 2×22/7×42×100
=> 2×22×6 ×100
26400cm² = 264m² area of roller in one complete revolution
1 revolution _______________264cm²
750 revolution ______________264×750
=> 198000 cm² Answer
or 198000/100 = 1980m²
**********************************
Hope it helps you !!
@Rajukumar
Given :- diameter of roller 84
r =42/2 cm
lenght /height of """"""""""" 1m =100cm
So, Curved surface area of road roller 2πrh because road roller is always in the form of cylindrical shape
so, 2×22/7×42×100
=> 2×22×6 ×100
26400cm² = 264m² area of roller in one complete revolution
1 revolution _______________264cm²
750 revolution ______________264×750
=> 198000 cm² Answer
or 198000/100 = 1980m²
**********************************
Hope it helps you !!
@Rajukumar
Anonymous:
THE ANSWER IS WRONG
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