Maths Question of linear equation in two variables :
Q: If x and y are the two digit of the number 653xy such that, these number is divisible by 80. Find the value of x and y.
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Answers
Answered by
26
80 = 5×2×8
653xy is divisible by 2 and 5 both, so y = 0
653x should be divisible by 8
It will be happen than x = 6
so x = 6 and y = 0
653xy is divisible by 2 and 5 both, so y = 0
653x should be divisible by 8
It will be happen than x = 6
so x = 6 and y = 0
Answered by
93
Answer :
x + y = 6 ( Option D )
Explanation :
Given that ,
653xy is divisible by 80.
In this case , we know the factors of 80 :-
80 = 5 × 16 ( Co - primes )
To be divisible by 5, the unit digit(y) should either be 0 or 5.
Means , y = 0 or 5.
Now , we include another factors of 80 :-
80 = 8 × 10
Here , the unit digit(y) should also be divisible by 10.
So , y = 0 or 5 ( where 5 by gets excluded )
Now ,
=> y = 0
So , now we have the number :- 653x0
Again , the divisibility of 16 says that all the last four digits should be divisible by 16 :-
=> 53x0/16
Assuming the value of x = 6.
After the division , ( refer to the attachment )
We obtain the results as :-
Quotient = 335
Remainder = 0
And X = 6.
Now ,
=> x = 6.
So , we have the values of both x and y i.e. 6 and 0 respectively.
Then ,
=> x + y = 6 + 0 = 6 ( Answer )
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