Question

maths question please answer 6 number question.plzzzzzzzzzzzzzzzzzzzzzzz​

Answer 1

Answer:

Step-by-step explanation:

Let the tens digit of the required number be x and the units digit be y. Then,

x+y=12  .........(1)

Required Number = (10x+y).

Number obtained on reversing the digits = (10y+x).

Therefore,

(10y+x)−(10x+y)=18

9y−9x=18

y−x=2     ..........(2)

On adding (1) and (2), we get,

2y=14⟹y=7

Therefore,  

x=5

Hence, the required number is 57.

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Answer 2

Answer:

let the tens digit be x,

so, ones digit = 12-x

the number =

$10x + (12 - x)$

$= 10x + 12 - x$

$= 9x + 12$

after interchanging the digits,

ones digit = x

tens digit = 12-x

the number =

$10(12 - x) + x$

$= 120 - 10x + x$

$= 120 - 9x$

according to the question,

$(120 - 9x) - (9x + 12) = 18$

$120 - 9x - 9x - 12 = 18$

$108 - 18x = 18$

$- 18x = 18 - 108$

$- 18x = - 90$

$x = \frac{ - 90}{ - 18} = 5$

so, the number=

$9x + 12$

$= 9 \times 5 + 12$

$= 45 + 12$

$= 57$

please mark it as the brainliest