Question

Maths question

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Answer 1

HEY MATE HERE IS YOUR ANSWER⭐

Step-by-step explanation:

log [ ( x + y )/3] = 1/2 ( logx + logy)

2× log[ ( x + y )/3 ] = log x + log y

log [ ( x + y ) / 3 ]^2 = log xy

{ since i ) n log a = log a^n

ii ) log a + log b = log ab }

Remove log bothsides,

[ ( x + y ) / 3 ]^2 = xy

( x + y )^2 / 3^2 = xy

x^2 + y^2 + 2xy = 9xy

x^2 + y^2 = 9xy - 2xy

x^2 + y^2 = 7xy

Divide each term with xy

x^2 / xy + y^2 / xy = 7xy / xy

x / y + y / x = 7

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Answer 2

Answer:

Step-by-step explanation

Content:

Logarithmic calculations:-

Formulae used:-

log(xy)=logx+logy

(x+y)^2=x^2+y^2+2xy

After solving,we get x^2+y^2=7xy

Bringing xy to LHS,we get:-

(x/y)+(y/x)=7

Answer is 7.