maths question............please answer it..... brainly users
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We know that diagonals of a rhombus bisect each other at 90 degrees.
So In triangle OPQ
we have
POQ+OPQ+OQP=180
90+30+x=180
so x=60
Now POQ is congruent to POS as OP=OP{common}
PS=PQ{sides of rhombus}
POQ=POS{90 degree}
So PQO=PSO{CPCT}
So x=y=60
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