maths question plz help trigonometric identities
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AR17:
sry....but do you need all the answer??
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Heya friend!!!
Please refer to the attachment for the answer.
But keep in mind these following things
◆cos²α + sin²α = 1
◆sec²α - tan²α = 1
◆cosec²α - cot²α = 1
◆cosβ × secβ = 1
◆sinβ × cosecβ = 1
◆tanβ × cotβ = 1
◆cos(90 - β) = sinβ
◆sin(90 - β) = cosβ
◆cosec(90 - β) = secβ
◆sec(90 - β) = cosecβ
◆tan(90 - β) = cotβ
◆cot(90 - β) = tanβ
Just keep this in mind and you can solve rest of the questions.
LET ME KNOW IF IT HELPS...... :-)
Please refer to the attachment for the answer.
But keep in mind these following things
◆cos²α + sin²α = 1
◆sec²α - tan²α = 1
◆cosec²α - cot²α = 1
◆cosβ × secβ = 1
◆sinβ × cosecβ = 1
◆tanβ × cotβ = 1
◆cos(90 - β) = sinβ
◆sin(90 - β) = cosβ
◆cosec(90 - β) = secβ
◆sec(90 - β) = cosecβ
◆tan(90 - β) = cotβ
◆cot(90 - β) = tanβ
Just keep this in mind and you can solve rest of the questions.
LET ME KNOW IF IT HELPS...... :-)
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late by few minutes i have solved it
but thanks
nice...
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thats your pic
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