Maths question
The base of an isosceles triangle is 4cm and its perimeter is 20cm. Find the area????
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perimeter=a+b+C
20=4+4+C........(2 sides. of isosceles ∆is equal)
20=8+C
C=20-8
C=12
area of triangle=1/2×base×height
=1/2×4×12
=24 sq.cm
20=4+4+C........(2 sides. of isosceles ∆is equal)
20=8+C
C=20-8
C=12
area of triangle=1/2×base×height
=1/2×4×12
=24 sq.cm
maneyamagan23:
thanks siram
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