Question

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Maths question

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✌The volume of a cone of base radius 3 centimetre is 12 cm cube find slant height....​

Answer 1

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Volume of cone = 12 cm

Radius of cone = 3 cm

Volume of cone

\begin{lgathered}= \frac{1}{3} \pi {r}^{2}h \\ \\ = > 12 = \frac{1}{3}\pi ({3})^{2}h \\ \\ = > \frac{12 \times 3}{9\pi} = h \\ \\ = > \frac{36 \times 7}{9 \times 22} = h \\ \\ = > \frac{28}{22} = h \\ \\\end{lgathered}

=

3

1

πr

2

h

=>12=

3

1

π(3)

2

h

=>

9π

12×3

=h

=>

9×22

36×7

=h

=>

22

28

=h

Hence h = 1.25 cm

slant height =

\begin{lgathered}\sqrt{ {h}^{2} + {r}^{2} } \\ \\ = \sqrt{ ({1.25})^{2} } + ({3})^{2} \\ \\ = \sqrt{1.5625} + 9 \\ \\ = \sqrt{10.5625} \\ \\ = 3.25 \: cm\end{lgathered}

h

2

+r

2

=

(1.25)

2

+(3)

2

=

1.5625

+9

=

10.5625

=3.25cm

Hence , slant height of cone

= 3.25 cm

Answer 2

Answer:

$\huge\mathfrak\red{hey\:mate}$

given that

volume of cone = 12cm

base = 3 cm

slant height = …?

volume of cone = 1/3πr^2h

h = volume × 3 /π r^2

h = 12 ×3/3.14 × 9

h = 4/3.14 π = 3.14

h = 1.27

now we know that

slant height. l= √ r^2+h^2

l = √ 10.61

l = 3.25 cm

$\huge\pink{Brainlist}$