Math, asked by EnoshGonmei, 1 year ago

Maths question. This it's making me confuse do please help me solving it. It's question number 11.

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Answered by dia1140

let one zero be

$\alpha \: and \: other \: is\: \frac{1}{ \alpha }$

$\alpha \times \frac{1}{ \alpha } = \frac{6}{ {a}^{2} - 9 } \\ 1 = \frac{6}{ {a}^{2} - 9 } \\ {a}^{2} - 9 = 6 \\ {a}^{2} = 9 + 6 \\ a = \sqrt{15}$

dia1140: no this question is alright ....i have just made the mistake

EnoshGonmei: Hmm..then do you know exactly how to solve it? If yes, then you can explain me in brief.

dia1140: yup

dia1140: see u just have to put 6a instead of 6 in the numerator then it would become a quadratic equation

dia1140: now solve the equation u will get the value of a

dia1140: actually i can't edit my answer as the time period has expired so i can help u out in the comments section

dia1140: if u have any kind of doubt then u can ask it here....i'll try my best to help u out

EnoshGonmei: Umm..thank you for the help. I think I would prefer asking my mathematics teacher after the holidays gets over. Thanks!

EnoshGonmei: It's literally confusing me up so much, and I'll check for it's solution later.

dia1140: ok

Answered by sparshsingh0506

Answer:

Maths question. This it's making me confuse do please help me solving it. It's question number 11.

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