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There are two triangles , ∆ADC and ∆ABC
AREA OF ∆ ADC ---
1/2 × DF × AC = 1/2 × 12 × 36 = 216 CM^2
AREA OF ∆ ABC ---
1/2 × BE × AC = 1/2 × 8 × 36 = 204 CM^2
SO , AREA OF QUADRILATERAL , ADD THE AREAS OF BOTH TRIANGLES --
216 + 204 = 420 CM^2 -- ANSWER
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